Question

A chord is at a distance of 12 cm from the centre of a circle of radius 13 cm. Find the length of the chord.​

Answer 1

Answer:

Hence, the length of the chord will be 10 cm.

Answer 2

Answer:

${\huge{\underline{\small{\mathbb{\pink{REFER \ TO \ THE \ ATTACHMENT}}}}}}$

Let AB the chord.

In right angled triangle AOM, given OA=13cm=radius.

OM= distance of centre O from the chord = 12cm

By Pythagoras theorem

${am}^{2} = {ao}^{2} - {om}^{2} \\ \\ = {13}^{2} - {12}^{2} \\ \\ = 25 \\ \\ {am}^{2} = 25 \\ \\ am = 5cm$

AM=5cm

Therefore, chord AB =2(AM)

=2×5=10cm

Hope it helps you from my side