Question

A chord is at a distance of 6 cm from the centre of a circle of radius 10 cm. The length of the chord is----​

Answer 1

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O is the centre of circle, radius of the circle=OA=r=10 cm, AB = ?, OC = 6 cm, C is point on chord AB & OC perpendicular to AB.

Now, In right triangle OAC,

By Pythagoras Theorem

OA ² = AC² + CO²

Or, AC² = OA² - CO²

Or, AC² = 10² - 6² = 100 - 36 = 64

Or, AC² = 100 - 36

Or, AC² = 64

Or, AC² = 8²

Or, AC = 8

Or AB = AC + CB

Or AB = 8 + 8 ----------- (AC = CB)

Or AB = 16 cm

Therefore, length of chord = AB = 16 cm

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Answer 2

Answer:

the lenght of the chord is 16 cm