Question

A chord is at a distance of 8 cm from the centre of a circle of radius 17 cm. The length of the chord is

Answer 1

Answer:

Hope it helps you.........

Answer 2

Answer:

Let AB be the chord with distance from the center =8 cm

OA=radius=17cm

Now, OC⊥AB

Then, AC=CB=

2

AB

.......(i)....(perpendicular drawn from the centre of the circle to the chord bisects the chord)

Now, △ACO is right angled triangle at C

∴AC=

(OA

2

−OC

2

)

=

(17

2

−8

2

)

=

(225)

=15cm

Hence, AB=2×15=30cm ............ From (i)

solution