Question

a chord is at a distance of 8cm from center . radius is 17cm , find the length of chord ​

Answer 1

Let AB be the chord with distance from the center =8 cm

OA=radius=17cm

Now, OC⊥AB

Then, AC=CB=

2

AB

.......(i)....(perpendicular drawn from the centre of the circle to the chord bisects the chord)

Now, △ACO is right angled triangle at C

∴AC=

(OA

2

−OC

2

)

=

(17

2

−8

2

)

=

(225)

=15cm

Hence, AB=2×15=30cm