A chord is at a distance of 8cm from the centre of a circle of radius 17cm. The length
of the chord is
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Answered by
2
Let AB be the chord with distance from the center =8 cm
OA=radius=17cm
Now, OC⊥AB
Then, AC=CB=
2
AB
.......(i)....(perpendicular drawn from the centre of the circle to the chord bisects the chord)
Now, △ACO is right angled triangle at C
∴AC=
(OA
2
−OC
2
)
=
(17
2
−8
2
)
=
(225)
=15cm
Hence, AB=2×15=30cm ...
Answered by
3
Answer:
The length of the chord is 30cm.
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