Question

a chord is used to lower vertically a block of mass M through a distance d at a constant downward acceleration g/3. The work done by the chord on the block is​

Answer 1

Answer:

May u got the ans in the above attachment

Answer 2

Answer:

The work done by the cord on the block is - 2 Mg d/3.

Explanation:

Given: Mass = M

  displacement = d

  downward acceleration g/3.

To find: Work done by the cord.

Solution: Through the concept of #Pseudo Force, we know that:

              Tension, T = m (g-a)

For the above case:

                    T = M ( g - g /3)

                   T = 2 Mg/3

#For work done, we know that:

                   W = F s cos∅

                   W = 2 Mg/3 × d × cos 180°

[∵ T = F = 2 Mg/3 and ∅ = 180° for the cord is descending straightly]

                   W = - 2 Mg d/3

Hence, the work done by the cord on the block is - 2 Mg d/3.