Question

A chord length 30 cm is drawn at a distance of 20 cm from the centre of the circle find the radius of circle​

Answer 1

Answer:

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Answer 2

17cm.

Answer:

Consider AB as as the chord of the circle with O as the centre

Construct OL ⊥ AB

From the figure we know that OL is the distance from the centre of chord It is given that AB = 30cm and OL = 8cm

Perpendicular from the centre of a circle to a chord bisects the chord

So we get AL = ½ × AB By substituting the values AL = ½ × 30

By division AL = 15cm Consider △ OLA

Using the Pythagoras theorem it can be written as OA2 = OL2 + AL2

By substituting the values we get OA2 = 82 + 152 On further calculation OA2 = 64 + 225 By addition OA2 = 289 By taking the square root OA = √289 So we get OA = 17cm

Therefore, the radius of the circle is 17cm.