A chord of 10 cm long is drawn in a circle whose radius is root 50cm. Find the areas of both the segments
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We have, radius, r = 5√2 cm and chord length, l = 10 cm. Now you can observe, ∆OAM & ∆OBM are isosceles & right angled at M. and the area of sector AOB = ¼(circle area) = (12.5)π cm², since angle AOB = 90°. Then area of segments are 50(π-2)/4 and 50(3π+2)/4.D
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