Question

a chord of 10m subtends an angle of 120° at the centre of the circle. Calculate its shortest distance from its centre.​

Answer 1

Answer:

Step-by-step explanation:

let the distance from the chord of the circle be 'x'.

Now,

In ΔOAC,

$tan 60= \frac{AC}{OC}\\ \sqrt{3}=\frac{5}{x}\\x=\frac{5}{\sqrt{3} }$

Answer 2

Answer:

see the attached diagram

Step-by-step explanation:

As per the given in question , we draw a figure of a circle with centre A,

Given , BC = 10 cm

AD ⊥ BC

∴ BD= 120°

∠BAD = = DC = 5 cm

∠BAC  60°

∠ABD = 30°

∴ In ∆ ABD,

tan30° =  AD /BD  

⇒  1 /√3 =AD /5

⇒ AD =  5/ √3 cm