a chord of a circle divide the circle into two parts such that the square inscribed in the two parts have area 16 and 144 square unit the radius of circle is
sivaprasath:
ok, I explain it below in few mins,.Plz wait,.
okk
excuse me, is it 10 root 2 (or) 2 root 10 ??
2 root 10
ohh,.
but except this there are 3 answer more given
what are they ?
6root 2, 9 and root 89
it is bit-confusy,. I will ask some maths aryabhatta to answer this Q,. if possible,.
ok.....
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From the square roots we can get the lengths of the two squares.
The smaller square :
√16 = 4 units
The bigger square :
√144 = 12 units
The length of the diagonal of the bigger square is :
Using Pythagoras theorem:
12² + 12² = 288
√288 = 16.97 units
From the center of the diagonal to one corner the length is:
16.97/2 = 8.485 units
We get the height from the center to half the length of the square using Pythagoras theorem.
The length = 12/2 = 6 units, the diagonal is 8.485cm
From Pythagoras theorem h is:
√(8.485² - 6²) = √(71.995 - 36) = 5.9996units
We add this to the length of the smaller square to get the radius of the circle :
5.9996 + 4 = 9.9996 units
The smaller square :
√16 = 4 units
The bigger square :
√144 = 12 units
The length of the diagonal of the bigger square is :
Using Pythagoras theorem:
12² + 12² = 288
√288 = 16.97 units
From the center of the diagonal to one corner the length is:
16.97/2 = 8.485 units
We get the height from the center to half the length of the square using Pythagoras theorem.
The length = 12/2 = 6 units, the diagonal is 8.485cm
From Pythagoras theorem h is:
√(8.485² - 6²) = √(71.995 - 36) = 5.9996units
We add this to the length of the smaller square to get the radius of the circle :
5.9996 + 4 = 9.9996 units
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