A chord of a circle has length 3n, where n is a positive integer. The segment cut off by the chord has height n, as shown. What is the smallest value of n for which the radius of the circle ia also a positive integer? Please do not add white space around the answe
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where is diagram for the question
krbagish96:
diagram is not given
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Thank you for asking this question, here is your answer:
We will consider the radius to be r
Chord length ,PQ = 3n
PB = BQ = PQ/2 = 3n/2 = 1.5n
OB = OA - AB = r - n
OQ = radius of circle = r
Here we will use the Pythagoras theorem
in ∆OBQ , OB² + BQ² = OQ²
now, (r - n)² + (1.5n)² = r²
r² + n² - 2rn + 2.25n² = r²
3.25n² - 2rn = 0
3.25n - 2r = 0
r = 3.25n/2 = 1.625n
Now we will chose the smallest positive integer for n and that would be 4
r = 1.625 × 4 = 6.5 ≠ integer
n = 8 , r = 1.625 × 8 = 13 = a positive integer
So we know that the smallest integer value is 8 now.
If there is any confusion please leave a comment below.
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