A chord of a circle is 10cm away from the centre.the ratio of the chord and the radius is 8:3.find the radius of the circle.
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2BC=AC
OA=10cm
let radius be 8@
so, length of chord will be 3@
in ∆OCB by Pythagoras theorem
8@*8@=100+3@*3@
64@^2=100+9@^2
55@^2=100
@^2=100/55
@^2=20/11
____
@=✓20/11=0.406
radius =8*0.406=3.252
OA=10cm
let radius be 8@
so, length of chord will be 3@
in ∆OCB by Pythagoras theorem
8@*8@=100+3@*3@
64@^2=100+9@^2
55@^2=100
@^2=100/55
@^2=20/11
____
@=✓20/11=0.406
radius =8*0.406=3.252
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