Question

A chord of a circle is 13.2 cm long and the circle's radius is 9.4 cm. Find the angle subtended by the chord at the centre of the circle.​

Answer 1

this is ur answer for ur question

Answer 2

Step-by-step explanation:

$For \: The \: Triangle \: ABO \: to \: find \: the \: length \: \: r\\\\ \: \: We \: have \: \\ \\ \\ \sin( \frac{ \alpha }{2} ) = \frac{opposite}{hypotenuse} \\ \\ = \frac{AB }{OA} \\ \\ = \frac{6.6}{9.4} \\ \\ = 0.70212 \\ \\ \\ where \: AB \: = \frac{13.2}{2} = 6.6cm \\ \\ \frac{ \alpha }{2} = \sin {}^{ - 1} \: \: (0.70212) \\ \\ then \: we \: optain \: = \\ \\ \alpha = 44.6° \times 2 \\ = 89.2°$

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The angle subtended by the chord at the center of the circle is 89.2°