a chord of a circle is 30 cm long its distance from the centre is 8 cm find the radius of the circle
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Answered by
16
Answer:
the chord will be perpendiculars it will form right angled triangle :
so r^2= {cord/2}^2 + {distance}^2
=> r^2= {15}^2 + {8}^2
=>r^2= 225 + 64
=>r^2=289
=>r=17
Answered by
6
Answer:
Step-by-step explanation:
given a chord length=30cm
distance of it from the center is 8cm
radius^2=(half of chord length)^2+(distance from the center^2)
r^2=15^2+8^2=225+64=289
r=17
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