Question

A chord of a circle is 36cm long. Its distance from the center is 4cm. Find the length of the radius​

Answer 1

Length of chord =24 cm

Length of chord =24 cmH 2 =B 2 +P 2 H= (12) 2 +(5) 2 ⇒H= 144+25 ⇒H= 169 ⇒H= (13) 2 ⇒H=13cm∴ Radius of the circle =13 cm.

Length of chord =24 cmH 2 =B 2 +P 2 H= (12) 2 +(5) 2 ⇒H= 144+25 ⇒H= 169 ⇒H= (13) 2 ⇒H=13cm∴ Radius of the circle =13 cm.Diameter of the circle =2×radius=2×13=26cm.

Answer 2

Answer:

8cm

Step-by-step explanation:

Give OC =4 cm, Chord AB =6 cm

∵OC⊥AB⇒bisectsAB

⇒AC=CB=3cm

∴InOCA,OA

2

+AC

2

(PythagorasTheorem)

=4

2

+3

2

=16+9=25

⇒OA=5cm

Let EF be the chord at a distance of 3cm from the centre.

GIven, radius=OE =5 cm

∴In△OGE,EG

2

=OE

2

−OG

2

=5

2

−3

2

=25−9=16

⇒EG=4cm

∴EF=2×EG=8cm