A chord of a Circle is equal to Its Radius then find the angle subtended by this chord at a point in major segment.
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Step-by-step explanation:
Let AB be the chord of the circle with center O.
Given that AB = Radius of the circle.
Also, AO = BO = Radius
∴ ΔOAB is an equilateral triangle.
Thus, ∠AOB = ∠OBA = ∠OAB = 60° Also, angle subtended by an arc at the center of the circle is twice the angle subtended by it at any other point in the remaining part of the circle.
∴ ∠AOB = 2∠ACB
⇒ ∠ACB = 1/2 (∠AOB)
⇒ ∠ACB = 1/2 (60°) = 30°
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30 degrees
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