a chord of a circle is equal to the radius of circle . find the angle subtended by the chord at a point on major arc.
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Answer:
Hence, the angle subtended by the chord at a point on the minor arc is 150° and also at a point on the major arc is 30°.
Step-by-step explanation:
Consider the figure.
Given,
AB is equal to the radius of the circle.
In △OAB,
OA=OB=AB= radius of the circle.
Thus, △OAB is an equilateral triangle.
and ∠AOC=60°.
Also, ∠ACB=21∠AOB=21×60°=30°.
Since, ACBD is a cyclic quadrilateral,
∠ACB+∠ADB=180° ....[Opposite angles of cyclic quadrilateral are supplementary]
⇒∠ADB=180°−30°=150°
hope its helpful
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