Question

A chord of a circle is equal to the radius of the circle. Find the angle subtended by the chord at a point on the minor arc and also at a point on the major arc.​

Answer 1

$\huge\mathfrak{Bonjour!!}$

$\huge\mathcal\purple{Answer:-}$

⏩ [Have a glimpse at the diagram above!]

As per the question,

OA= AB = OB

Therefore,

∆OAB is an equilateral triangle.

=> angle AOB = 60°

=> angle ACB = 1/2 angle AOB

[Angle subtended by an arc at the centre is twice the angle at the remaining circle]

=> angle ACB = 1/2 × 60°

=> angle ACB= 30°

Now,

angle ACB + angle ADB = 180°

[opposite angles of cyclic quadrilaterals are supplementary]

=> angle ADB = 180° - angle ACB

=> angle ADB= 180° - 30° = 150°

✔✔✔✔✔✔✔

Hope it helps...:-)

⭐♥✨❤⭐♥✨❤⭐

Be Brainly...✌✌✌

♣ CABELLOER ♠

Answer 2

Answer:

plzz give me brainliest ans and plzzzz follow me