Question

a chord of a circle is equal to the radius of the circle.Find the angle subtended by the chord at a point on the minor arc and also at a point on the major arc.

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Answer 1

Step-by-step explanation:

this is your answer to the question

Answer 2

Answer :

The chord AB is equal to the radius of the circle.

OA and OB are the two radii of the circle.

From △OAB.

AB circle. = OA = OB = radius of the

AOAB is an equilateral triangle.

.. AOC = 60°

$And,∠ACB = \frac{1}{2} ∠AOB$

$So, ∠ACB = \frac{1}{2} \times 60° = 30°$

Now, ACBD is a cyclic quadrilateral,

∠ADB + ∠ACB = 180° (Since they are the

opposite angles of a cyclic quadrilateral)

So, ∠ADB = 180° -30° = 150°

Hence, the angle subtended by the

chord at a point on the minor arc and

also at a point on the major arc is 150 &

30° respectively.