Question

A chord of a circle of 14cm subtends a right angle at Center . What is the area of the minor sector ?

Answer 1

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Answer 2

Answer:

77 cm² (Refer to attachment for drawing)

Step-by-step explanation:

Length of chord = 14cm

Angle subtended = 90°

In ΔOAB, ∠O= 90° and OA = OB = r (radii of a circle)

∴ΔOAB is Right angled isosceles triangle. So, using pythagoras theorem,

r²+r² = 14²

2r²=196 => r²=98

fArea of minor sector = $\frac{Θ}{360}$ × π × r²

                                = $\frac{90}{360}$ × $\frac{22}{7}$ × 98

                               = $\frac{1}{4}$ ×22×14

                               = 77 cm²