a chord of a circle of a radius 28cm subtends a right angle at the centre . what is the area of the minor sector ?( π 22/7).
Answers
Answer:
Given radius of circle = 28cm.
We know that Area of the whole circle = pir^2
= 22/7 * (28)^2
= 2464sq.cm.
We know that Area of the minor sector = theta/360 * pir^2
= 90/360 * pir^2
= 90/360 * 2464
= 616sq.cm
Answer:
Step-by-step explanation:
Given radius of circle = 28cm.
We know that Area of the whole circle = pir^2
= 22/7 * (28)^2
= 2464sq.cm.
We know that Area of the minor sector = theta/360 * pir^2
= 90/360 * pir^2
= 90/360 * 2464
= 616sq.cm