Question

A
chord of a circle of
rading 5cm sublende
are angle of 45
at the centred find
the area cal
minor segments
Circle​

Answer 1

Step-by-step explanation:

⇒ Here, r=5cm and θ=90

o

⇒ Area of sector OABO=

360

θ

πr

2

=

360

o

90

o

×3.14×(5)

2

∴ Area of sector OABO=

4

3.14×25

=19.62cm

2

⇒ Area of △AOB=

2

1

×AO×BO=

2

1

×5×5

∴ Area of △AOB=

2

25

=12.5cm

2

∴ Area of minor segment made bye the chord AB = Area of sector OABO - Area of △AOB

∴ Area of minor segment made bye the chord AB =19.62−12.5=7.12cm

2

⇒ Area of circle =πr

2

=3.14×(5)

2

∴ Area of circle =78.5cm

2

⇒ Area of major segment made by chord AB = Area of a circle - Area of minor segment.

∴ Area of major segment made by chord AB=78.5−7.12=71.38cm

2