A chord of a circle of radius 10 cm makes a right angle at the centre. Find the
areas of the minor and major segments of the circle. ( = 3.14)
45) Two dice are tossed together write all possible outcomes of this experiment.
Find the probability of getting
(i) 7 as the sum
(ii) a sum greater than 10.
(iii) a sum less than 13.
Answers
Answered by
1
Step-by-step explanation:
Area of minor segment (shaded region) = Area of the quadrant AOB− Area of the △AOB
=
4
1
×πr
2
−
2
1
×AO×OB
=
4
1
×3.14×(10 cm)
2
−
2
1
×10 cm×10 cm
=
4
1
×3.14×100 cm
2
−50 cm
2
=78.5 cm
2
−50 cm
2
=28.5 cm
2
(ii) Area of the major segment = Area of the circle − Area of the minor segment
=πr
2
−28.5 cm
2
=3.14×(10 cm)
2
−28.5 cm
2
=314 cm
2
−28.5 cm
2
=285.5 cm
2
Similar questions