Question

A chord of a circle of radius 10 cm subtends 90° at the centre. Find the area of the minor segment. [π=3.14] ​

Answer 1

Answer:

78.5 cm²

Step-by-step explanation:

Area of sector = (90 ÷ 360) × 3.14 × (10 cm)²

= 0.25 × 3.14 × 100 cm²

= 78.5 cm²

Answer 2

Answer:

In the mentioned circle

O is the centre and AO=BO = Radius = 10 cm.

AB is a chord which subtends 90° at centre O, i.e. /AOB =90°

( I ) area of minor segment APB (shaded region)

= area of sector AOB - area of / AOB

=( π × 10 × 10 ) / 4 = ( 0.5×10×10)

=78.5 - 50

=28.5cm2

( ii ) area of major sector = area of circle - area of sector AOB

= (π ×10×10) - ( π × 10×10) /4

=314 - 78.5

= 235.5 cm2

Step-by-step explanation:

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