A chord of a circle of radius 10 cm. Subtends a right angle at the centre. Find the area of the corresponding : (i) minor segment (ii) major sector.(use p= 3.14)
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Answered by
6
Answer:
U
Step-by-step explanation:
Ar. Of minor segment=at. Of sector- area of triangle
=(πr^2)/4 -1/2r^2
=π×100/4 -100/2
=100(π-2)
=100(3.14-2)=114
Major sector =(πr^2)3/4
=(3.14×100)3/4=235.5
Answered by
24
Answer:
Minor segment= 28.5 sq. cm.
Major segment = 285.5 sq. cm.
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