A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the
the corresponding: (i) minor segment (ii) major sector. (Use ¶ = 3.14)
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Minor segemet area=θ/360×πr²-1/2bh
1/4×3.14×10×10-½10×10
78.5-50
=28.5cm²
Major sector area =360-θ/360×πr²
360-90/360×3.14×10²
¾×314=235.5cm²
1/4×3.14×10×10-½10×10
78.5-50
=28.5cm²
Major sector area =360-θ/360×πr²
360-90/360×3.14×10²
¾×314=235.5cm²
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