Question

A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of
the corresponding : (i) minor segment (ii) major sector (Use 3.14)
​

Answer 1

In the mentioned circle,

O is the centre and AO =BO = Radius = 10 cm

AB is a chord which subtents 90 o

at centre O, i.e., ∠AOB=90 o

(i)

Area of minor segment APB (Shaded region) = Area of Sector AOB - Area of △AOB

=( 4π×10×10 )−(0.5×10×10)

=78.5−50

=28.5cm 2

(ii)

Area of Major sector = Area of circle - Area of Sector AOB

= (π×10×10)−( 4π×10×10 )

=314−78.5

=235.5cm 2