Question

A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:

(i) minor segment

(ii) major sector. (Use π = 3.14)
class 10 {chapter 12}

Answer 1

$\rm\underline\bold{Question \purple{\huge{\checkmark}}}$

A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:

(i) minor segment

(ii) major sector. (Use π = 3.14)

class 10 {chapter 12}

$\huge{\tt{\colorbox{blue}{AnswEr:}}}$

In the mentioned circle,

O is the centre and AO =BO = Radius = 10 cm

AB is a chord which subtents 90o at centre O, i.e., ∠AOB=90o

(i)

Area of minor segment APB (Shaded region) = Area of Sector AOB - Area of △AOB

=(4π×10×10)−(0.5×10×10)

=78.5−50

=28.5cm2

(ii)

Area of Major sector = Area of circle - Area of Sector AOB

= (π×10×10)−(4π×10×10)

=314−78.5

=235.5cm2

Answer 2

Answer:

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Step-by-step explanation:

Question✓

A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:

(i) minor segment

(ii) major sector. (Use π = 3.14)

class 10 {chapter 12}

\huge{\tt{\colorbox{blue}{AnswEr:}}}

AnswEr:

In the mentioned circle,

O is the centre and AO =BO = Radius = 10 cm

AB is a chord which subtents 90o at centre O, i.e., ∠AOB=90o

(i)

Area of minor segment APB (Shaded region) = Area of Sector AOB - Area of △AOB

=(4π×10×10)−(0.5×10×10)

=78.5−50

=28.5cm2

(ii)

Area of Major sector = Area of circle - Area of Sector AOB

= (π×10×10)−(4π×10×10)

=314−78.5

=235.5cm2