Question

A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of
the corresponding: (i) minor segment (ii) major sector. (Use = 3.14)​

Answer 1

Answer:

i) 28.5 sq. cm

ii) 285.5 sq. cm

Step-by-step explanation:

area of minor segment

= (3.14×10×10)/4 -(10×10)/2

=78.5-50

= 28.5 sq. cm

area of major sector is

= 3.14×10×10 - 28.5

=314 - 28.5

=285.5 sq. cm

Answer 2

Question:-

A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:

(i) minor segment (ii) major sector. (Use = 3.14)

Answer:-

In the mentioned circle,

O is the centre and AO=BO=Radius=10cm

AB is a chord which subtents 90° at centre O,i,e.,$\angle$AOB =90°

(i)

Area of minor segment APB (Shaded region) = Area of sector AOB - Area of AOB

= $(\frac{\pi \times 10 \times 10}{4}) - (0.5 \times 10 \times 10)$

= 78.5 - 50

= 28.5 cm²

(ii)

Area of major sector = Area of Circle - Area of sector AOB

= $(\pi \times 10 \times 10) - ( \frac{\pi \times 10 \times 10}{4})$

= 314 - 78.5

= 235.5 cm²

_____________________________

Know More :-

What is the minor segment?

The minor segment is the region bounded by the chord and the minor arc intercepted by the chord.

What is major segment?

The major segment is the region bounded by the chord and the major arc intercepted by the chord.

What is Circle of radius?

Ans:-A line from the center of the circle to a point on the circle.