Question

a chord of a circle of radius 10 cms is making an angle of 60°at the circle .find the length of the circle​

Answer 1

• The radius of the circle = 10 cm.

• Chord PQ subtends an angle = 60 degrees at the centre.

• PQO is an equilateral triangle,

• O being the centre of the circle.

• Area of minor segment = θ/360 x π r2 – 1/2 r2 sinθ

= 60/360 x 22/7 x 10 x 10 – 1/2 x 10 x 10 x √3/2

= 9.03 Area of circle

= πr2 = 22/7 x 10 x 10 = 314 (approx.)

Area of minor segment = Area of circle – Area of minor segment

= 314 – 9.03 = 304.97 cm2 (approx.)