Question

A chord of a circle of radius 100 cm subtends a right angle at the center. Find the following: (Use π = 3.14)

(i) area of minor sector (ii) length of the arc (iii) area of major segment​

Answer 1

Answer:

O is the centre and AO =BO = Radius = 10 cm

AB is a chord which subtents 90o at centre O, i.e., ∠AOB=90o

(i)

Area of minor segment APB (Shaded region) = Area of Sector AOB - Area of △AOB

=(4π×10×10​)−(0.5×10×10)

=78.5−50

=28.5cm2

(ii)

Area of Major sector = Area of circle - Area of Sector AOB

= (π×10×10)−(4π×10×10​)

=314−78.5

=235.5cm2

well i hope this will help u

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Step-by-step explanation: