A chord of a circle of radius 10cm subtends a right angle at the centre .Find the area of the corresponding minor sector, major sector, minor segment and major segment
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given= radius 10cm subtends a right angle at the centre.
step by step explanation :-
Let AB be the chord of the circle subtending 90° angle at centre O of the circle.
Area of major sector OADB =3/4 x 3.14 x 10 x 10=235.5cm2 .
Area of minor sector OACB = =1/4 x 3.14 x 10 x 10= 78.5cm2.
Area of trangle OAB = =50 cm2Area of minor segment ACB = Area of minor sector OACB - Area of ΔOAB = 78.5 - 50 = 28.5 cm2
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