Question

A chord of a circle of radius 10cm subtends a right angle at the centre. What is the length length of the chord.

Answer 1

Answer:-

Radius is = 10cm

So ,

Applying phythogorus

in ∆Aop

Ap = √10² + 10²

Ap = √200

Ap = 10√2

Answer 2

$<b>$
Solution:-

$= > {(ab)}^{2} = {(oa)}^{2} + {(ob)}^{2} \\ \\ = > {x}^{2} = {10}^{2} + {10}^{2} \\ \\ = > {x}^{2} = 100 + 100 \\ \\ = > {x}^{2} = 200 \\ \\ = > x = \sqrt{200} \\ \\ = x = 14.14$

Hence,

The length of chord is 14.14 cm.