A chord of a circle of radius 12 subtends an angle of 120 ° at the centre . Find the area of the corresponding segment of circle.
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Given:-
- A chord of a circle of radius 12 cm subtends an angle of 120 ° at the centre.
To find:-
- The area of the corresponding segment of circle.
Solution:-
Here,
- Radius of circle = 12 cm
- θ = 120°
According to the question,
→ Area of the segment = {(π/360) × θ - sin θ/2 cos θ/2} r²
→ Area of the segment = {(π) × 120/360 - sin 120/2 cos 120/2 } 12²
→ {(π) × ⅓ - sin 60° cos 60° } × 144
→ (π/3 - ½ × √3/2) × 144
→ (π/3 × 144 - 144 × √3/4
→ 48π - 36√3
→ 12(4π - 3√3)
→ 12(4 × 3.14 - 3 × 1.73)
→ 12 (12.56 - 5.19)
→ 12 × 7.37
→ 88.44 cm²
Hence,
- the area of the corresponding segment of the circle is 88.44 cm².
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