Question

A chord of a circle of radius 14 cm subtends an angle of 60° at the centre. Find the area of the corresponding minor segment of the circle. ( Use π=22/7 and √3 = 1.73)​

Answer 1

area of segment minor =¥r^2ø%360 - 1/2 r^2:sin ø

22/7×14×14×60/360 - 1/2 ×14 ×14 × 1.732

22× 14 /3 - 49 ×1.732

$308 \div 3 - 49 \times 1.732$

=17.798