a chord of a circle of radius 14cm subtend an angle of 120 at the centre find the area of the corresponding minor segment of a circle
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radius r=14cm
angle subtended =120
area of the sector A=120/360xpir^2
A=1x3.14x14x14/3
A=615.44/3
A=205.147sq.cm
let the radius and the angle form an arc AOB
area of AOB=1/2r^2 sin120
AOB=14X14X0.866/2
AOB=84.868 Sq.cm
therefore area of the minor segment =araeA-area of AOB
area of minor segment =205.147-84.868
=120.297sq.cm
angle subtended =120
area of the sector A=120/360xpir^2
A=1x3.14x14x14/3
A=615.44/3
A=205.147sq.cm
let the radius and the angle form an arc AOB
area of AOB=1/2r^2 sin120
AOB=14X14X0.866/2
AOB=84.868 Sq.cm
therefore area of the minor segment =araeA-area of AOB
area of minor segment =205.147-84.868
=120.297sq.cm
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