Question

A chord of a circle of radius 14cm subtends a right angle at the center.What is the area of minor sector

Answer 1

Given r = 14cm

Given angle = 90degrees

Area of minor sector = [(given angle)/360] * $\pi r^2$

= 90/360 * 3.14 * 14²

= 0.25 * 3.14 * 196

= 153.86

Therefore, area of minor sector is 153.86 cm²