Question

a chord of a circle of radius 14cm subtends the angle at centre. find the area of minor sector ​

Answer 1

adius(r)=14cm

⇒ Area of sector OABO= θ/360 πr²

∴ Area of sector OABO= 90⁰/360⁰×22/7×(14)²=

154cm²

⇒ Area of right angled △OAB= 1/2×14×14=98cm²

∴ Area of the minor segment of the circle = Area of sector OABO - Area of righta angled △ABO

∴ Area of the minor segment of the circle =(154−98)cm2 =56cm²

⇒ Area of circle =πr2= 22/7 ×14×14= 616 cm²q

⇒ Area of the major segment of the circle = Area of circle - Area of minor segment.

∴ Area of the major segment of the circle =(616−56)cm2=560cm²

hope.it helps......