Question

a chord of a circle of radius 15 CM subtends an angle of 60 degree at the centre find the area of the corresponding minor or major segment of the circle​

Answer 1

Heya,
.Area of sector ABCD =πr^2¢/360°

=)22/7×15×15×60°/360°

=)117.85.

Area of ∆ABC.

=1/2r^2sin¢

=)1/2×15×15×√3/2

=)225√3/4

=)97.3125.

minor segment BDC=Area of sector ABDC-Area of triangle ABC.
=117.85-97.3125
=)20.53 ___1)

and again ,Area of circle =πr^2¢

=)22/7×15×15

=)707.14.cm^2.
.
so, major segment BDC
=)Area of circle - minor segment.

=)707.14-20.5

=)686.642 Ans


hope it help you.

Answer 2

Answer:

Step-by-step explanation: