a chord of a circle of radius 15 CM subtends an angle of 60 degree at the centre find the area of the corresponding minor or major segment of the circle
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.Area of sector ABCD =πr^2¢/360°
=)22/7×15×15×60°/360°
=)117.85.
Area of ∆ABC.
=1/2r^2sin¢
=)1/2×15×15×√3/2
=)225√3/4
=)97.3125.
minor segment BDC=Area of sector ABDC-Area of triangle ABC.
=117.85-97.3125
=)20.53 ___1)
and again ,Area of circle =πr^2¢
=)22/7×15×15
=)707.14.cm^2.
.
so, major segment BDC
=)Area of circle - minor segment.
=)707.14-20.5
=)686.642 Ans
hope it help you.
.Area of sector ABCD =πr^2¢/360°
=)22/7×15×15×60°/360°
=)117.85.
Area of ∆ABC.
=1/2r^2sin¢
=)1/2×15×15×√3/2
=)225√3/4
=)97.3125.
minor segment BDC=Area of sector ABDC-Area of triangle ABC.
=117.85-97.3125
=)20.53 ___1)
and again ,Area of circle =πr^2¢
=)22/7×15×15
=)707.14.cm^2.
.
so, major segment BDC
=)Area of circle - minor segment.
=)707.14-20.5
=)686.642 Ans
hope it help you.
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