Question

A chord of a circle of radius 15cm subtends an angle of 60' at the center. Find the area of the corresponding minor and major segment of the circle.

Answer 1

Answer:

Area of sector ABCD =πr^2¢/360°

=)22/7×15×15×60°/360°

=)117.85.

Area of ∆ABC.

=1/2r^2sin¢

=)1/2×15×15×√3/2

=)225√3/4

=)97.3125.

minor segment BDC=Area of sector ABDC-Area of triangle ABC.

=117.85-97.3125

=)20.53 ___1)

and again ,Area of circle =πr^2¢

=)22/7×15×15

=)707.14.cm^2.

.

so, major segment BDC

=)Area of circle - minor segment.

=)707.14-20.5

=)686.642 Ans