a chord of a circle of radius 20 centimetre substance and angle of 90 degree at the centre of the circle find the area of the corresponding major segment of the circle
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use this formula then your answer will be there
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Ayush12711:
ohoo ok wait
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I really hope it ll help u.
Area of the circle =πr^2=1256cm2
Area of the sector =90/360×3.14×20×20=314cm2
Area of triangle=1/2×20×20=200cm2
So,area of minor segment=314-200=114cm2
Then,area of major segment=1256-114=1142cm2
Area of the circle =πr^2=1256cm2
Area of the sector =90/360×3.14×20×20=314cm2
Area of triangle=1/2×20×20=200cm2
So,area of minor segment=314-200=114cm2
Then,area of major segment=1256-114=1142cm2
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