Question

A chord of a circle of radius 20 cm subtends an angle of 90 degree at the centre. find the area of the corresponding major segment of the circle

Answer 1

Area of the minor segment = { pi × 90 /360 - sin 45 × cos 45 } × r × r

={ 3.14 ×1/4 - 1÷√2 ×1÷√2 } × 20 × 20

= { 3.14 × 1/4 - 1÷2 } × 400

= 3.14 × 400 ÷ 4 - 400 ÷ 2

= 3.14 × 100 - 200

= 314-200

=114

Area of circle = pi × r × r

= 3.14 × 20 × 20

= 3.14 × 400

= 1256

Area of major segment = area of circle - area of minor segment

= 1256 - 114

= 1142

HOPE IT HELPS YOU

Answer 2

PLZZ check the attachment for answer..... Hope it is help full