A chord of a circle of radius 20 cm subtends an angle of 90 degree at the center . Find the area of the corresponding major segment of the circle.
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Secondary SchoolMath 13 points
A chord of a circle of radius 20 cm subtends an angle of 90 degree at the centre. find the area of the corresponding major segment of the circle
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Area of the minor segment = { pi × 90 /360 - sin 45 × cos 45 } × r × r
={ 3.14 ×1/4 - 1÷√2 ×1÷√2 } × 20 × 20
= { 3.14 × 1/4 - 1÷2 } × 400
= 3.14 × 400 ÷ 4 - 400 ÷ 2
= 3.14 × 100 - 200
= 314-200
=114
Area of circle = pi × r × r
= 3.14 × 20 × 20
= 3.14 × 400
= 1256
Area of major segment = area of circle - area of minor segment
= 1256 - 114
= 1142
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