A chord of a circle of radius 20 cm subtends an angle of 90° at the centre. Find the area of the corresponding major segment of the circle.
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Answer:
1142
Step-by-step explanation:
Area of circle=πr²
=πr²
=314/100*20*20
=1256 cm²
area of minor segment =theta/360*πr² -1/2*r²sin theta
=90*314*20*20/360*100 -1/2*20²(1)
=314-200
114cm²
area of major segment=area of circle -area of minor segment
=1256-114
=1142 cm²
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