A chord of a circle of radius 20cm subtends an angle of 90° at the centre.Find the area of the corresponding major segment of the circle
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Radius =20cm
theta= 90°
area of minor segment = πr²theta/360-1/2r²sintheta
= 22/7×20×20×90/360-1/2×20×20×sin90°. [sin90°=1]
Solve this u will the area of minor segment..
Therefore,
major segment = πr²-(@rea of minor segment)
theta= 90°
area of minor segment = πr²theta/360-1/2r²sintheta
= 22/7×20×20×90/360-1/2×20×20×sin90°. [sin90°=1]
Solve this u will the area of minor segment..
Therefore,
major segment = πr²-(@rea of minor segment)
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