Question

a chord of a circle of radius 21 cm subtends an angle of 60 degree at the centre. find the area of the corresponding minor segment of the circle. use π=22/7 and √3 = 1.73

Answer 1

Answer:  Area of corresponding minor segment of the circle is 40.26 cm² .

Step-by-step explanation:

Since we have given that

Radius of circle = 21 cm

Angle subtended by the chord = 60°

As we know the formula for "Area of sector":

$\frac{\theta}{360}\times \pi r^2\\\\=\frac{60}{360}\times \frac{22}{7}\times 21\times 21\\\\=231\ cm^2$

And we know the formula for "Area of triangle":

Since it is an equilateral triangle as two of its angle is 60°.

$Area=\frac{\sqrt{3}}{4}\times r^2\\\\Area=\frac{1.73}{4}\times 21\times 21\\\\Area=190.73\ cm^2$

Now, Area of corresponding minor segment of the circle is given by

$\text{ Area of sector-Area of triangle}\\\\=213-190.73\\\\=40.26\ cm^2$

Hence, Area of corresponding minor segment of the circle is 40.26 cm² .

Answer 2

Step-by-step explanation:

please see from photo

sorry for bad writing