Math, asked by sharmi76, 1 year ago

a chord of a circle of radius 21 cm subtends an angle of 60° at the centre.find the area of the corresponding minor segment of the circle

shalu4056: π ki value kya h

sharmi76: 22/7

shalu4056: or √3 ki

sharmi76: 1.73

shalu4056: ok

shalu4056: mane splve kr diaa ha but pic kase snd krte h i did't know

sharmi76: oo . it's ok

shalu4056: plz..btao

Answers

Answered by Anonymous

ATTACHMENT__✍️

MARK BRAINLIEST✓✓✓

Attachments:

sharmi76: the ans must be 40.05

Anonymous: Ya!! may be, your ans. come If area of sector=231cm^2- area of triangle AOB = MINOR sector so, 231cm^2- 190.95cm^2= 40.05 cm^2 ans.

sharmi76: hmmm

Anonymous: Now please mark BRAINLIEST okk

sharmi76: okk

Answered by Amudevasani

Answer:

231 cm²

Step-by-step explanation:

r =21 cm

θ = 60°

minor segment = θ/360*πr²

60/360*22/7*21*21

11*21

231 cm²

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