Question

A chord of a circle of radius 21cm subtends an angle of 60° at the centre. Find the area of the corresponding minor segment of the circle. ​

Answer 1

Answer:

Step-by-step explanation:

Area of segment = Area of sector - Area of triangle

= Ф/ 360 x π r² - r² sinФ/2 cosФ/2

=1/6 x 22/7 x 21 x 21 x √3/4

= 21 ( 11 - 21√3/4 ) m²

Answer 2

area of minor segment = teta/ 360 into pie radius square

= 60/360 into 22/7 into 7

= 6 into 22/7

= 18.8

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