Question

A chord of a circle of radius 28cm subtends an angle of 45° at the centre of the circle.Find the area of minor segment.​

Answer 1

$answer$

given, radius of circle = 28 cm

and angle A=45°

Area of sector=A /360° Tr^2

=45/360 x 22/7 x 28 x 28

=( 22 x 4 x 28 )/ 8

=2464/8

=308 cm^2

therefore, the required area of minor sector = 308 cm^2

Your Answer: 308 cm^2