Question

A chord of a circle of radius 6cm is making an angle 60 at home length of the chord​

Answer 1

Step-by-step explanation:

IN TRIANGLE AOB, AO=BO=6cm

THEREFORE,∠OAB=∠OBA=y(say)

IN TRIANGLE AOB BY ANGLE SUM PROPERTY

60°+y+y=180°⇒180°-60°=2y⇒120°=2y⇒y=60°

THEREFORE AS ∠A=∠B=∠C=60°

THEREFORE TRIANGLE AOB IS AN EQUILATERAL TRIANGLE

⇒LENGTH OF CHORD AB =6cm

Answer 2

Answer:

please refer to the given attachment...

hope it helps dear...